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python:将数字转换成用英文表达的程序

 
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前几天无意中看到了一篇文章列了很多数字的英文表达方式(http://blog.csdn.net/sun7545526/article/details/8122416),正好这段时间在学习python,所以写了个简单的程序用来将数字翻译成英文的表达方式,例如输入123,返回 one hundred and twenty-three ,目前该程序可以表示的范围为0-999,999,999,999.由于本人是个python新手,所以如果用的不完善的地方,还请帮忙改正


'''
convert number to string, number range is 0-999,999,999,999 and must be integer
Created on 2012-10-31

@author: Eric

'''
import locale;

NUMBER_CONSTANT = {0:"zero ", 1:"one", 2:"two", 3:"three", 4:"four", 5:"five", 6:"six", 7:"seven",
                8:"eight", 9:"nine", 10:"ten", 11:"eleven", 12:"twelve", 13:"thirteen",
                14:"fourteen", 15:"fifteen", 16:"sixteen", 17:"seventeen", 18:"eighteen", 19:"nineteen" };
IN_HUNDRED_CONSTANT = {2:"twenty", 3:"thirty", 4:"forty", 5:"fifty", 6:"sixty", 7:"seventy", 8:"eighty", 9:"ninety"}
BASE_CONSTANT = {0:" ", 1:"hundred", 2:"thousand", 3:"million", 4:"billion"};
#supported number range is 1-n billion;
def translateNumberToEnglish(number):
    if str(number).isnumeric():
        if str(number)[0] == '0' and len(str(number)) > 1:
            return translateNumberToEnglish(int(number[1:]));
        if int(number) < 20:
            return NUMBER_CONSTANT[int(number)];
        elif int(number) < 100:
            if str(number)[1] == '0':
                return IN_HUNDRED_CONSTANT[int(str(number)[0])];
            else:
                return IN_HUNDRED_CONSTANT[int(str(number)[0])] + "-" + NUMBER_CONSTANT[int(str(number)[1])];
        else:
            locale.setlocale(locale.LC_ALL, "English_United States.1252");
            strNumber = locale.format("%d"    , number, grouping=True);
            numberArray = str(strNumber).split(",");
            stringResult = "";
            groupCount = len(numberArray) + 1;
            for groupNumber in numberArray:
                if groupCount > 1 and groupNumber[0:] != "000":
                    stringResult += str(getUnderThreeNumberString(str(groupNumber))) + " ";
                else:
                    break;
                groupCount -= 1;
                if groupCount > 1:
                    stringResult += BASE_CONSTANT[groupCount] + ",";
            endPoint = len(stringResult) - len(" hundred,");
            #return stringResult[0:endPoint];
            return stringResult;
                
    else:
        print("please input a number!");

#between 0-999
def getUnderThreeNumberString(number):
    if str(number).isnumeric() and len(number) < 4:
        if len(number) < 3:
            return translateNumberToEnglish(int(number));
        elif len(number) == 3 and number[0:] == "000":
            return " ";
        elif len(number) == 3 and number[1:] == "00":
            return NUMBER_CONSTANT[int(number[0])] + "  " + BASE_CONSTANT[1];
        else:    
            return NUMBER_CONSTANT[int(number[0])] + "  " + BASE_CONSTANT[1] + " and " + translateNumberToEnglish((number[1:]));
    else:
        print("number must below 1000");
    

def testTranslateNumberToEnglish():
       print("0: " + translateNumberToEnglish(0));
       print("9: " + translateNumberToEnglish(9));
       print("33: " + translateNumberToEnglish(33));
       print("40: " + translateNumberToEnglish(40));
       print("100: " + translateNumberToEnglish(100));
       print("103: " + translateNumberToEnglish(103));
       print("123: " + translateNumberToEnglish(123));
       print("1,121,912  " + translateNumberToEnglish(1121912));
       print("211,121,900  " + translateNumberToEnglish(211121900));
       print("11,000,000  " + translateNumberToEnglish(11000000));
       print("1,111,121,912  " + translateNumberToEnglish(111121912));
       print("2,211,121,900  " + translateNumberToEnglish(2211121900));
       print("1,111,000,000  " + translateNumberToEnglish(1111000000));

if __name__ == '__main__':
    testTranslateNumberToEnglish();

输出的结果为:

0: zero
9: nine
33: thirty-three
40: forty
100: one hundred
103: one hundred and three
123: one hundred and twenty-three
1,121,912 one million,one hundred and twenty-one thousand,nine hundred and twelve
211,121,900 two hundred and eleven million,one hundred and twenty-one thousand,nine hundred
11,000,000 eleven million,
1,111,121,912 one hundred and eleven million,one hundred and twenty-one thousand,nine hundred and twelve
2,211,121,900 two billion,two hundred and eleven million,one hundred and twenty-one thousand,nine hundred
1,111,000,000 one billion,one hundred and eleven million,

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